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Consider A = l¥. Define E = {(xn) Î l¥ ; x2n = 0} and F = {(xn) Î l¥ ; x2n-1 = 0}. Obviously E and F are closed subalgebras of l¥. Moreover A = E+F and EÇF = {0}. So E is a complemented subspace of A with F as a complementary subspace. In addition, j((x1,x2,x3,¼)) = (0,x1,0,x2,0,x3,¼) is an isometrically isomorphism between l¥ and E. One can similarly define an isomorphism between l¥ and F. Note that if E is a complemented infinite dimensional subspace of l¥ then E is isomorphic to l¥. (cf. [J. Lindenstranss, On complemented subspaces of m. Israel J. Math., 5, 1967, 153-156])