On a separable infinite dimensional Banach On a separable infinite dimensional Banach space X there exists another norm under which X isn't separable.

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Suppose that {ei ; i Î I} is a Hamel basis for X and I is countable. For each i Î I, let Xi denote the linear span of {e1, e2, ¼, en}, then X = Èi = 1nXi. But the Xi are proper closed subspaces of X and so are nowhere dense, that is impossible by the Baire category theorem. Thus I is uncountable.
Let a Î X, a = åi Î I li ei where all l except finitely many are zero. Set ||a ||¢ = åi Î I |li|. Then ||. ||¢ is obviously a norm on X. For i ¹ j , ||ei - ej ||¢ = 2 and I is uncountable, hence (X,||. ||¢) has no dense countable subset.


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On 22 Feb 2001, 00:18.