Given a compact subset Given a compact subset K of C, there exists a bounded operator T on a Hilbert space such that sp(T) = K and the set of eigenvalues of T is dense in K.

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Suppose that H = l2,  (en) is the standard orthonormal basis for H and (ln) is a dense sequence in K. Set T(ån = 1¥ anen) = ån = 1¥ln an en where (an) Î l2. Obviously K Í sp(T). If l Ï K, then inf{|l- m|; m Î K } > 0 and so S(ån = 1¥an en) = ån = 1¥(l- ln)-1an en is a well-defined operator on H. S is the inverse of lI - T. Therefore l Ï sp(T). Thus K = sp(T).
For every n,   Ten = ln en. In fact {l1, l2, ¼} is the set of all eigenvalues of T that is dense in sp(T).


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On 22 Feb 2001, 00:21.